Boundary Atlas

Griffith, Indiana

Griffith is a town in Lake County, Indiana, with 16,520 residents in 2020. It is in Indiana's 1st congressional district. Its state senate district is State Senate District 1; its state house district is State House District 12.

16,520residents (2020 Census)
7.8 sq miland area
2ZIP codes
1congressional district

County

CountyShare of residents
Lake County100%

Congressional district

Congressional districtShare of residents
Indiana's 1st congressional district (IN-01)100%

Elected officials

OfficeMemberContactShare of residents
U.S. Representative (IN-01)Frank J. Mrvan (D)202-225-2461100%
U.S. SenatorJim Banks (R)202-224-4814statewide
U.S. SenatorTodd Young (R)202-224-5623 · contact formstatewide
State Senator (State Senate District 1)Dan Dernulc (R)100%
State Representative (State House District 12)Mike Andrade (Democratic)100%

Officials serving now (members of Congress until January 3, 2027). Sources: State legislators: Open States (public domain); Members of Congress: the @unitedstates project, congress-legislators (CC0).

Local government

State legislative districts

State senate districtShare of residents
State Senate District 1100%

State house districtShare of residents
State House District 12100%

ZIP codes

Percentages mark ZIPs only partly in Griffith: the share of that ZIP's residents living in it.

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Griffith here is the Census Bureau's place boundary as of January 1, 2025. Shares are of 2020 Census population. Districts are the maps in force for the November 3, 2026 election.